Generate All Combinations Of Key Value Pairs Java
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- Generate Public and Private Keys. In order to be able to create a digital signature, you need a private key. All key pair generators share the concepts of a keysize and a source of randomness. Such as when creating high-value and long-lived secrets like RSA public and private keys.
- How to generate unique combinations in Excel? Supposing you have three lists, and now you want to generate unique combinations from these three lists as below screenshots shown, and how can you quickly solve this troublesome problem in Excel? Then in the List All Combinations dialog, select Value from Type drop down list.
- Adding Key-Value Pairs: 9.48.3. Get all keys and elements from a hash table: 9.48.4. Copying all the key-value pairs from one Hashtable (or any Map) into another Hashtable: the putAll method: 9.48.5. Displaying Hash Table Contents: 9.48.6. Removing Key-Value Pairs: call the remove method with the specific key as its argument: 9.48.7.
Nov 01, 2017 I have a list with 15 numbers in, and I need to write some code that produces all 32,768 combinations of those numbers. I’ve found some code (by Googling) that apparently does what I’m looking for, but I found the code fairly opaque and am wary of using it. Plus I have a feeling there must be a more elegant solution.
For the desired output we can assume that the productAttribute parameter value is 'Computer'.
Current output of the addProduct ArrayList:
Desired output of the addProduct ArrayList:
I can't seem to figure out what I'm doing wrong. Any help would be greatly appreciated.
Generate All Combinations Of Key Value Pairs Java In Excel
Well, looking at the lists of Strings you have in your example, I don't understand why they are lists of Strings. To me they ought to be some kind of objects which are designed specifically for these products, because obviously the first entry in the list is some kind of a category, the second entry is a manufacturer, and so on. Just putting those things in a list is a misuse of lists.
And likewise I don't see the point of making a slightly different list which just has the product code on the front. Perhaps it should be part of the product object which I was just suggesting. Making a list of products would make a lot of sense once you've done that, which is basically your non-OO requirement anyway.
I have a list with 15 numbers in, and I need to write some code that produces all 32,768 combinations of those numbers.
I’ve found some code (by Googling) that apparently does what I’m looking for, but I found the code fairly opaque and am wary of using it. Plus I have a feeling there must be a more elegant solution.
The only thing that occurs to me would be to just loop through the decimal integers 1–32768 and convert those to binary, and use the binary representation as a filter to pick out the appropriate numbers.
Does anyone know of a better way? Using map()
, maybe?
Generate All Combinations Of Key Value Pairs Javascript
Have a look at itertools.combinations:
Return r length subsequences of elements from
the input iterable.
Combinations are emitted in lexicographic sort order. So, if the
input iterable is sorted, the
combination tuples will be produced in
sorted order.
Since 2.6, batteries are included!
This answer missed one aspect: the OP asked for ALL combinations… not just combinations of length “r”.
So you’d either have to loop through all lengths “L”:
Or — if you want to get snazzy (or bend the brain of whoever reads your code after you) — you can generate the chain of “combinations()” generators, and iterate through that:
Here’s a lazy one-liner, also using itertools:
Main idea behind this answer: there are 2^N combinations — same as the number of binary strings of length N. For each binary string, you pick all elements corresponding to a “1”.
Things to consider:
- This requires that you can call
len(..)
onitems
(workaround: ifitems
is something like an iterable like a generator, turn it into a list first withitems=list(_itemsArg)
) - This requires that the order of iteration on
items
is not random (workaround: don’t be insane) - This requires that the items are unique, or else
{2,2,1}
and{2,1,1}
will both collapse to{2,1}
(workaround: usecollections.Counter
as a drop-in replacement forset
; it’s basically a multiset… though you may need to later usetuple(sorted(Counter(..).elements()))
if you need it to be hashable)
Demo
I agree with Dan H that Ben indeed asked for all combinations. itertools.combinations()
does not give all combinations.
Another issue is, if the input iterable is big, it is perhaps better to return a generator instead of everything in a list:
This one-liner gives you all the combinations (between 0
and n
items if the original list/set contains n
distinct elements) and uses the native method itertools.combinations
:
The output will be:
Try it online:
In comments under the highly upvoted answer by @Dan H, mention is made of the powerset()
recipe in the itertools
documentation—including one by Dan himself. However, so far no one has posted it as an answer. Since it’s probably one of the better if not the best approach to the problem—and given a little encouragement from another commenter, it’s shown below. The function produces all unique combinations of the list elements of every length possible.
Note: If the, subtly different, goal is to obtain only combinations of unique elements, change the line s = list(iterable)
to s = list(set(iterable))
to eliminate any duplicate elements. Regardless, the fact that the iterable
is ultimately turned into a list
means it will work with generators (unlike several of the other answers).
Output:
You can generating all combinations of a list in python using this simple code
Result would be :
Here is yet another solution (one-liner), involving using the itertools.combinations
function, but here we use a double list comprehension (as opposed to a for loop or sum):
Demo:
Below is a “standard recursive answer”, similar to the other similar answer https://stackoverflow.com/a/23743696/711085 . (We don’t realistically have to worry about running out of stack space since there’s no way we could process all N! permutations.)
It visits every element in turn, and either takes it or leaves it (we can directly see the 2^N cardinality from this algorithm).
Demo:
I thought I would add this function for those seeking an answer without importing itertools or any other extra libraries.
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Simple Yield Generator Usage:
Output from Usage example above:
[] , [1] , [2] , [1, 2] , [3] , [1, 3] , [2, 3] , [1, 2, 3] , [4] ,
[1, 4] , [2, 4] , [1, 2, 4] , [3, 4] , [1, 3, 4] , [2, 3, 4] , [1, 2,
3, 4] ,
Generate All Combinations Of Key Value Pairs Javascript W3
This code employs a simple algorithm with nested lists…
I know it’s far more practical to use itertools to get the all the combinations, but you can achieve this partly with only list comprehension if you so happen to desire, granted you want to code a lot
For combinations of two pairs:
And, for combinations of three pairs, it’s as easy as this:
Generate All Combinations Of Key Value Pairs Java 1
The result is identical to using itertools.combinations: